3n^2+6n-144=0

Solution for 3n^2+6n-144=0 equation:

3n^2+6n-144=0

a = 3; b = 6; c = -144;
Δ = b2-4ac
Δ = 62-4·3·(-144)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-42}{2*3}=\frac{-48}{6}
=-8
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+42}{2*3}=\frac{36}{6}
=6
$